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3x^-6x=3x^2+5x-11
We move all terms to the left:
3x^-6x-(3x^2+5x-11)=0
We add all the numbers together, and all the variables
-3x-(3x^2+5x-11)=0
We get rid of parentheses
-3x^2-3x-5x+11=0
We add all the numbers together, and all the variables
-3x^2-8x+11=0
a = -3; b = -8; c = +11;
Δ = b2-4ac
Δ = -82-4·(-3)·11
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-14}{2*-3}=\frac{-6}{-6} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+14}{2*-3}=\frac{22}{-6} =-3+2/3 $
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